引用:
function mydata(){
xmlhttp_init();
rech();
var ajax_ly_num = document.getElementById("ajax_ly_num");
var ajax_pl_num = document.getElementById("ajax_pl_num");
var ajax_hot = document.getElementById("ajax_hot");
//alert(ajax_hot);
var aa = "<br>";
var news_id = document.getElementById('news_id').value;
//alert(news_id);
xmlhttp.open("POST","../../news_data.php?time="+new Date().getTime(),true);
xmlhttp.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
xmlhttp.send("news_id="+news_id);
xmlhttp.onreadystatechange=function(){
if (xmlhttp.readyState==4 || xmlhttp.readyState=="complete"){
ajax_hot.innerHTML = xmlhttp.responseText;
var array = eval('('+xmlhttp.responseText+')');
var num = array.num;
var hot = array.hot;
var aa ="343434";
alert(aa);
ajax_ly_num.innerHTML = num.ll_num;
ajax_pl_num.innerHTML = num.pl_num;
for(i=0;i<hot.length;i++){
var title = hot[i].title;
var imgsrc = hot[i].imgsrc;
var aa = aa+"<div style='border:#FF0000 solid 1px'><div><img width='80%' src="+imgsrc+"></div><div>"+title+"</div></div><br>" ;
}
ajax_hot.innerHTML = aa;
}
}
}
变量在后台返回值前赋值,提示是undefined
变量在后台返回值后赋值,赋值就成功
var ajax_ly_num = document.getElementById("ajax_ly_num");
在后台返回值前取得对象,在后台返回值后,依然有效
变量aa在后台返回值后就失效了,为什么?